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12c^2-36c=0
a = 12; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·12·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*12}=\frac{0}{24} =0 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*12}=\frac{72}{24} =3 $
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